Answer:
AFCE = 30
P+Q = 11
Step-by-step explanation:
From the picture, you can see the figure can be decomposed into two identical large triangles with area 20, and 4 identical longer ones, that have to cover the remaining area 40, thus 10 each.
From that you can count the area.
Second puzzle is just trial and error.
Answer:
p=7x
Step-by-step explanation:
49x^[2] + 28x - 10 = p^[2] + 4p -10
This equation is in the form a^[2]x + bx + c.
<u><em>The 'c' is common for both equations, this means the 'a' and 'b' must also be common. </em></u>
There are two ways to find p: 'a' or 'b'
<u>a method</u>
49x^[2] = p^[2]
=> The square root of both sides = 7x = p
<u>b method</u>
28x = 4p
28x/4 = 4p/4
7x = p
Answer:
4,099 and 5,011
Step-by-step explanation:
This problem can be solved by taking options one by one.
Option (1) : 4,099
Digit in ones place = 9
The value of the digit in tens place = 90
. It is correct.
Option (2) : 4,110
Digit in one places = 0
The value of the digit in tens place = 10
It is incorrect.
Option (3) : 5,909
Digit in one places = 9
The value of the digit in tens place = 0
It is again incorrect.
Option (4) : 5,011
Digit in one places = 1
The value of the digit in tens place = 10
. It is correct.
Hence, in option (a) and (d), the he ones place is 1/10 the value of the digit in the tens place.
Answer:
i think its c im not sure so it might be wrong im so sorry if its wrong
Step-by-step explanation: