Question

Help me im so sad determine the values of X for which f(x) is defined ​

Answer 1

Answer:

$f(x) = \frac{(2x - 1)(3x - 2)}{9x - 4} \\ open \: brackets \\ = \frac{(6 {x}^{2} - 4x - 3x + 2) }{9x - 4} \\ = \frac{6 {x}^{2} - 7x + 2 }{9x - 4} \\ let \: x \: be \: 1 \\ f(1) = \frac{(6 - 7 + 2)}{(9 - 4)} \\ = \frac{1}{5}$