We know for our problem that the zeroes of our quadratic equation are
and
, which means that the solutions for our equation are
and
. We are going to use those solutions to express our quadratic equation in the form
; to do that we will use the <span>zero factor property in reverse:
</span>
<span>
</span>
<span>
Now, we can multiply the left sides of our equations:
</span>
<span>= </span>
=
=
Now that we have our quadratic in the form
, we can infer that
and
; therefore, we can conclude that
.
Answer:
7-4=3
6-2=4
-3-2= -5
-8+9=1
-9+5= -4
1+10=11
Step-by-step explanation:
No es tan difícil, puedes g0oglearlo
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
To get the answer you would subtract 11% from 100%, getting the answer 89%.
