The answer would be 9(8b+5)
this is how you do it...
1. find the GCF of both numbers in this one the GCF would be 9
now, what do you multiply 9 by to get 72... 8, so 8 would go into the parenthesis and because there is a variable there which is 'b' the 8 would become '8b' now what do you multiply 9 with to get 45? '5' so you would add 5 into the parenthesis and that would be your answer!
Hope this helped! :D
Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
Answer:
correct choice is 1st option
Step-by-step explanation:
Two given triangles have two pairs of congruent sides: one pair of length 7 units and second pair of length 8 units. The third side is common, i.e the lengths of third sides are equal too.
Use SSS theorem that states that if three sides of one triangle are congruent to three sides of another triangle, then these two triangles are congruent.
Thus, given triangles are congruent by SSS theorem.
If a variable is binomially distributed with n trials and a success probability of p, then the mean = np, variance = np(1–p) and standard deviation = square root of variance.
In this case, n = 1200, p = 0.35. So, mean = (1200)(0.35) = 420,
variance = (1200)(0.35)(1–0.35) = 273,
standard deviation = square root of variance = √273 = 16.52.
Answer:
a)
b)
Step-by-step explanation:
From the question we are told that:
3 coin are tossed
Therefore
Sample space
Generally the sets that correspond with the result of at most one tail is therefore given as follows
Therefore
The result is at most one tail when