Make an equation system based on the problem
eg. a is the first number and b is the seond number
An equation for "<span>The sum of two numbers is 53" is
</span>⇒ a + b = 53
An equation for "<span>twice the first number minus three times the second number is 26"
</span>⇒ 2a - 3b = 26
<span>
Solve the equations by elimination and subtitution method
Eliminate a to find the value of b
a + b = 53 (multiplied by 2)
2a - 3b = 26
--------------------------------------
2a + 2b = 106
2a - 3b = 26
------------------- - (substract)
5b = 80
b = 80/5
b = 16
Subtitute the value of b to one of the equations
a + b = 53
a + 16 = 53
a = 53 - 16
a = 37
The numbers are 16 and 37</span>
4b+20 because you disrepute the 4
Answer:
According to me the answer should be 'a'
(2.5,150)(4,240)
slope = (240 - 150) / (4 - 2.5) = 90 / 1.5 = 60
y = mx + b
slope(m) = 60
(4,240)...x = 4 and y = 240
now we sub and find b, the y int
240 = 60(4) + b
240 = 240 + b
240 - 240 = b
0 = b
so ur equation is : y = 60x + 0 which is written as : y = 60x <==