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2 years ago

12

I need some help please

1 answer:

Nadya [2.5K]2 years ago

4 0

Answer: I: (3, +infinity) D: (-infinity, 3) (this is the fourth answer)

Step-by-step explanation: The graph is decreasing left to right until 3, and begins to increase from left to right beginning at 3.

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The ratio of the geometric mean and arithmetic mean of two numbers is 3:5, find the ratio of the smaller number to the larger nu

IgorC [24]

Answer:

$\frac{1}{9}$

Step-by-step explanation:

Let the numbers be x,y, where x>y

The geometric mean is

$\sqrt{xy}$

The Arithmetic mean is

$\frac{x + y}{2}$

The ratio of the geometric mean and arithmetic mean of two numbers is 3:5.

$\frac{ \sqrt{xy} }{ \frac{x + y}{2} } = \frac{3}{5}$

We can write the equation;

$\sqrt{xy} = 3$

or

$xy = 9 - - - (2)$

l

and

$\frac{x + y}{2} = 5$

or

$x + y = 10 - - - (2)$

Make y the subject in equation 2

$y = 10 - x - - - (3)$

Put equation 3 in 1

$x(10 - x) = 9$

$10x - {x}^{2} = 9$

${x}^{2} - 10x + 9 = 0$

$(x - 9)(x - 1) = 0$

$x =1 \: or \: 9$

When x=1, y=10-1=9

When x=9, y=10-9=1

Therefore x=9, and y=1

The ratio of the smaller number to the larger number is

$\frac{1}{9}$

3 0

2 years ago

I need help quick please

qwelly [4]

A=90
B=53
The reason I am saying this is because you can see the 90 degree angle in A

8 0

1 year ago

Read 2 more answers

49x^2 + 42xy + 9y^2 Factor completely.

mario62 [17]

(7x-3y)^2 hope this helps

6 0

2 years ago

Read 2 more answers

Find the solutions x2 = 27

Aneli [31]

Answer:

27 divided by 3 is 9

27 divided by 2 is 13.5

x = 13.5

Re written...

(13.5)2 = 27

make sense?

7 0

2 years ago

Compute the difference quotient StartFraction f left parenthesis x plus h right parenthesis minus f left parenthesis x right par

kenny6666 [7]

Answer:

$\dfrac{f(x+h) - f(x)}{h}=-8x-4h-3$

Step-by-step explanation:

$f(x)=-4x^2-3x-4$

$f(x+h)=-4(x+h)^2-3(x+h)-4$

$f(x+h)=-4(x^2+2xh+h^2)-3(x+h)−4$

$f(x+h)=-4x^2-8xh-4h^2-3x-3h-4$

$f(x+h) - f(x)=-4x^2-8xh-4h^2-3x-3h-4-(-4x2-3x-4)$

$f(x+h) - f(x)=-4x^2-8xh-4h^2-3x-3h-4+4x2+3x+4$

$f(x+h) - f(x)=-8xh-4h^2-3h$

$f(x+h) - f(x)=h(-8x-4h-3)$

$\dfrac{f(x+h) - f(x)}{h}=\dfrac{h(-8x-4h-3)}{h}$

$\dfrac{f(x+h) - f(x)}{h}=-8x-4h-3$

7 0

2 years ago