Answer:
$755
Step-by-step explanation:
You can use the formula c = 60m + 35 for this. c is the cost and m is the number of months. Since a year is 12 months, 60m = 60*12 = 720. Then add the one time fee of $35. 720 + 35 = 755.
Answer:
tan 11 pi dived by 6 is equal to -118.307586549
Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
Answer:
6 =k
Step-by-step explanation:
Given the equation for inverse variation
xy = k
We know x=-3 and y = -2
Substituting these values in
(-3) (-2) = k
6 =k
Answer:
1 7/8 quarts
Step-by-step explanation:
The amount Yuan has left can be found by multiplying the original amount by the fraction he has left.
__
<h3>used</h3>
After using 1/2 of the broth for soup, the fraction remaining is ...
1 -1/2 = 1/2
The amount Yuan used for gravy is 1/4 of this, or ...
(1/4)(1/2) = 1/8 . . . of the original amount of broth
The total fraction Yuan used was ...
fraction used = fraction for soup + fraction for broth = 1/2 +1/8 = 5/8
<h3>remaining</h3>
Then the fraction remaining is ...
fraction remaining = 1 - fraction used = 1 - 5/8 = 3/8.
The amount remaining is this fraction of the original amount:
(3/8)(5 quarts) = 15/8 quarts = 1 7/8 quarts . . . . remaining
.</h2><h2>~</h2><h3>To find the answer, simply factor 2 out of 2x^2+4x+6 to get your final answer, </h3><h3>2(x^2 + 2x + 3)</h3><h2>~</h2><h3>Thank you for taking the time to read this!</h3><h3><u>And I hope you have a good day, Loves!</u></h3><h3><em><u>Also if I'm right can you let me know, please?</u></em></h3>