Answer:
Teo is 11 years old and Richard is 26 years old.
Step-by-step explanation:
Let R be the age of Richard and T be the age of Teo.
<u><em>First set up the equations:</em></u>
The combined age of Teo and Richard is 37:
R+T=37
Richard is four years old than twice Teo's age:
R=2T+4
<u><em>Then, solve the equations:</em></u>
Substitute (2) to (1) and solve for T:
(2T+4)+T=37
3T=11
T=11
Solve for R using (2):
R=2(11)+4
R=22+4
R=26
Answer:
<em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>
Step-by-step explanation:
<u>f</u><u>{</u><u>5</u><u>}</u> = <u>6</u><u>(</u><u>5</u><u>^</u><u>2</u><u>)</u><u> </u><u>+</u><u> </u><u>2</u><u>(</u><u>5</u><u>)</u><u> </u><u>-</u><u> </u><u>7</u>
g{-3}= 4(-3)-3
= <u>6</u><u>(</u><u>2</u><u>5</u><u>)</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u> </u><u>-</u><u> </u><u>7</u>
-12 - 3
= <u>150</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u> </u><u>-</u><u> </u><u>7</u>
- 15
= <u>1</u><u>5</u><u>3</u>
-15
= <u>-</u><u>5</u><u>1</u>
5
= <em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>
x=4 y=5
if we put two pharases together
the answer is as follows pic :
x=4 y=5
Answer:
Expand it.
(1+2i)^3 is equal to (1+2i)(1+2i)(1+2i).
Multiply everything out (being sure to multiply <em>every</em> term. (1+2i) * (1+2i) = 1+2i+2i+4i^2.
i is the square root of negative one, so i^2 is just -1. 1+2i+2i-4 is what you get from the first two, so now simplify that:
1-4 + 2i+2i = (-3+4i) and now multiply that by (1+2i):
(-3+4i) * (1+2i) = -3 - 6i +4i +8i^2.
Simplify again, and the answer is: -11-2i
Step-by-step explanation:
I hope this helps - really my only tip is don't spend time thinking about what i is, that just hurts your brain. Just remember that i^2 is equal to negative one, and treat it like regular multiplication and you will be fine.
Answer:
Step-by-step explanation:
3 * 1/2 * 5 * 4.5
= 33.75 fT^2.