Answer:
10.76 grams
Explanation:
Given that the amount of is 25.0 grams.
Mass of 1 mole of = 158 grams
The number of atoms in 1 mole of is 4.
Mass of oxygen in 1 mole of = 16\times 4 = 68 grams.
Here, 158 grams of has 68 grams of oxygen
So, the amount of oxygen in 1 gram of = 68/158 grams
Therefore, the amount of oxygen in 1 gram of =
grams
=10.76 grams
Hence, 25 grams of has 10.76 grams of oxygen.
Answer: 10.2 grams
Explanation:
The balanced chemical reaction is :
According to the ideal gas equation:
P = Pressure of the gas = 740 torr = 0.97 atm (760torr=1atm)
V= Volume of the gas = 12.0 L
T= Temperature of the gas = 19°C = 292 K
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas
According to stoichiometry:
2 moles of hydrogen are generated by = 1 mole of
Thus 0.48 moles of hydrogen are generated by = moles of
Mass of
Thus 10.2 grams of are needed to generate 12.0 L of hydrogen gas if the pressure of hydrogen is 740. torr at 19°C