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2 years ago

⚠️⚠️What is the output value, if the input value is 30?⚠️⚠️ THIS IS MY LAST ONE HELP

Mathematics

1 answer:

lora16 [44]2 years ago

7 0

Answer:

Step-by-step explanation:

15 is half of 30, the output values are the input values divided by 2 :)

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Solve the equation thanks

sashaice [31]

X=-2y+3
Is your answer hope this helps

4 0

2 years ago

Todd’s average score for six tests was 92. If the sum of the scores of two of her tests was 188, then what was her average score

natita [175]

Answer:

Step-by-step explanation:

Todd’s average score for six tests = 92.

The sum of two of her test = 188

First, we need to find the total score for the six test. This given below:

Average = sum of all test / number of test

sum of all the test = average x number of test

average score for six tests = 92.

Number of test = 6

Sum of all the Tests = 92 x 6 = 552

Sum of four test = sum of all the test — sum of two test

Sum of four test = 552 — 188 = 364

Now we can solve for the average of the other four test as shown below:

Average of four test = 364/4= 91

3 0

2 years ago

Read 2 more answers

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

2 years ago

I WILL MARK YOU BRAINLIEST!!!!!

iren2701 [21]

Answer:

C. one solution

Step-by-step explanation:

The number of solutions can be found from the number of intersection points.

There are 2 lines, a parabola (curve) and a horizontal line that is parallel to the x axis.

We see that there is 1 point of intersection between the 2 lines, at (2,1)-right 2 and up 1. Therefore, this non linear system has 1 solution.

C. one solution is the correct answer.

7 0

2 years ago

In the past month, Hans rented 1 video game and 3 DVDs. The rental price for the video game was $2.40. The rental price for each

soldi70 [24.7K]

Answer:

$10.80

Step-by-step explanation:

$2.40 + $2.80(3)

$2.40 + 8.40

5 0

2 years ago

Read 2 more answers