First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
Answer:
(2×3)¹
(11×1)¹
Step-by-step explanation:
2×3=6 so 2 to the power 1 is 2 and 3 to the power 1 is 3 so 2×3=6
11×1=11 so 11 to the power 1 is 11 and 1 to the power 1 is 1 so 11×1 =11
Answer: (2x - 1)(3x - 4)
(split -11x as -8x and -3x)
Step-by-step explanation:
I am assuming that it is actually 6x^2 - 11x + 4
To find out how to split the middle term: The two numbers should multiply to a*c (6*4 = 24) and add to b (-11)
-8, -3 works
(6x^2 - 8x) + (-3x + 4)
2x(3x - 4) + -1(3x - 4)
(2x - 1)(3x - 4)
A. 12% discount, or, $7.44 discount
B. The sale price is $54.56
