Answer:
H3PO4 Mol mass..
= (3 x H1 = 3) + (1 x P31 = 31) + (4 x O16 = 64). = 98g/mol.
a)..Hydrogen: = 3 / 98 = 0.0306 x 100% = 3.06%.
b)..Phosphorus = 31/98 = 0.3162 x 100% = 31.63%.
c)..Oxygen = 64/98 = 0.6531 x 100% = 65.31%.
(Total = 100% H3PO4).
Explanation:
Find the molar mass of all the elements in the compound in grams per mole.
Find the molecular mass of the entire compound.
Divide the component's molar mass by the entire molecular mass.
You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.
Answer:
H2 + I2 --> 2HI
Explanation:
The two reactants are diatomic molecules because they contain two atoms of the same element. Therefore, they would need to have a subscript of "2" next to their symbols.
When balancing an equation, you want the same amount and type of atoms on both sides. By adding a coefficient of "2" in front of the product, two H's and two I's are now on both sides.
<span>Answer:
3 electron pairs
Let's take BF3 for an example.
When you find the valence electrons for this molecule --> [3+(3x6)], you'll get 24e-. You draw the Lewis dot structure and each of the F atom would have six dots around it (a total of 18 because there's 3 F atoms) and the B would have three lines [one line attached to each F. One line would equal to 2 valence electrons] and you get a total of 24 valence e-.
The question asks how many groups are on the CENTRAL atom, meaning on the B. It would be three</span>
Answer:
9.28 g/L
Explanation:
We will be using the ideal gas law to solve this problem:
PV = nRT where P is the pressure (atm)
V is the volume (L)
R is the gas constant 0.08205 Latm/Kmol
T is the temperature (K)
n is the number of moles
The number of moles is the mass divided by the molecular weight, and from here we can solve for the density. (Note here we use the atomic weight of radon since its is a monoatomic noble gas)
PV = m/AW RT ⇒ P = (m/V ) RT/AW ⇒ P AW /RT =D
0.950 atm x 222.0 g/mol / [( 0.08205 Latm/Kmol ) x 277 K ] = D
9.28 g/L = D
One MOLE of hydrogen atoms contains the same number of atoms as the number of hydrogen molecules in one MOLE of hydrogen molecules, i.e., Avagadros number. However, one mole of hydrogen atoms has a mass of 1 gram while one MOLE of hydrogen molecules has a mass of 2 grams
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