Answer:
A baseball (m= 149g) approaches a bat horizontally at a speed of 40.2 m/s (90 mi/h) and is hit straight back at a speed of 45.6m/s (102mi/h). If the ball is in contact with the bat for a time of 1.10ms, what is the average force exerted on the ball by the bat ? Neglect the weight of the ball, since it is so much less than the force of the bat. Choose the direction of the incoming ball as the positive direction.
Explanation:
Use the impulse equation (a form of Newton's 2nd Law): FΔt = Δ(mv) where Δ means "change in"
The change in momentum is mBB(vf - vi) = (.150 kg)(-46.9 m/s - 40.5 m/s)
Divide this by the time interval and you get F exerted by the bat in Newtons.
Take care.
Answer:
320N
Explanation:
The magnitude of the torque required is expressed using the formula;
T = Fr sin theta where;
F is the force
r is the radius = 9cm = 0.09m
theta is the angle of inclination = 8 degrees
Torque T = 4Nm
Substitute the given values and get F
4 = F(0.09)sin8
4 = 0.0125F
F = 4/0.0125
F = 320N
Hence the magnitude of the force required when the force is applied at 8 degrees to the wrench is 320N
The position of the sun and the moon affect how high the tide is
Metamorphism occurs because some minerals are stable only under certain conditions of pressure and temperature. When pressure and temperature change, chemical reactions occur to cause the minerals in the rock to change to an assemblage that is stable at the new pressure and temperature conditions.
The distance between the two charges is 
Explanation:
The electrostatic force between two charged objects is given by Coulomb's law:
where:
is the Coulomb's constant
are the charges of the two objects
r is the separation between the two charges
In this problem, we are given the following:
Therefore, we can rearrange the equation to solve for r, the distance between the two charges:
Learn more about electrostatic force:
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