Answer:
None of the options are correct. The correct answer is:
56.67g
Explanation:
N2 + 3H2 —> 2NH3
Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol
Mass of NH3 from the balanced equation = 2 x 17 = 34g
Molar Mass of H2 = 2x1 = 2g/mol
Mass of H2 from the balanced equation = 3 x 2 = 6g
From the equation,
6g of H2 produced 34g of NH3.
Therefore, 10g of H2 will produce = (10 x 34)/6 = 56.67g of NH3
Therefore, 56.67g of NH3 are produced
134.5 grams in 4.5 moles of Li2O (lithium oxide).
Explanation:
When the reaction takes place,2 grams of carbon dioxide will be made but vaporized into air.
Answer:
0.50 M
Explanation:
Given data
- Mass of sodium sulfate (solute): 7.1 g
- Volume of solution: 100 mL
Step 1: Calculate the moles of the solute
The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:
Step 2: Convert the volume of solution to liters
We will use the relation 1 L = 1000 mL.
Step 3: Calculate the molarity of the solution