The second law of motion states that: the acceleration of an object is dependent upon two variables: - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object
<h3>Meaning of Motion</h3>
Motion can be defined as the process of changing position willingly or due to a force applied.
Motion can be seen in different forms and types depending on the object.
In conclusion, The second law of motion is used to deduce the formula for acceleration.
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The current that would pass through the 30 ohms resistor is 2 A.
<h3>What is electric current?</h3>
Electric current is the rate of flow of electric charge round a conductor.
To calculate the electric current that would pass through the 30 ohms resistor, we use the formula below
Formula:
- I = V/Rt........... Equation 1
Where:
- I = Electric current passing through the 30 ohms resistor
- V = Voltage
- Rt = Total or effective resistance of the resistors.
From the question,
Given:
- V = 100 volts
- Rt = (30+20) ohms (since both resistors are connected in series)
Substitute these values into equation 1
Hence, The current that would pass through the 30 ohms resistor is 2 A.
Learn more about electric current here: brainly.com/question/1100341
Question: A loader sack of total mass
is l000 grams falls down from
the floor of a lorry 200 cm high
Calculate the workdone by the
gravity of the load.
Answer:
19.6 Joules
Explanation:
Applying
W = mgh........................ Equation 1
Where W = Workdone by gravity on the load, m = mass of the loader sack, h = height, g = acceleration due to gravity
From the question,
Given: m = 1000 grams = (1000/1000) kilogram = 1 kg, h = 200 cm = 2 m
Constant: g = 9.8 m/s²
Substitute these values into equation 1
W = (1×2×9.8)
W = 19.6 Joules
Hence the work done by gravity on the load is 19.6 Joules
Use the kinematic equation: Vf=Vi+at
Then plug;
Vi=14 m/s
a=5 m/s²
t=20 s. Therefore;
Vf=14+(5*20)
Vf=114 m/s.
Throw it sideways and try to make it spin around but it needs to be thrown high up then it should kinda glide down
