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2 years ago

What is the formula to calculate the readings on an ammeter?

2 answers:

8 0

An ammeter works like a galvanometer except for the existence of a resistance that is attached in parallel. The pointer will have torque on it because of the coil. The equation is expressed as:
<span>
S = G/n-1 </span>
where G is the main resistance and S is the shunt resistance while n is a range ratio.

Cloud [144]2 years ago

4 0

If the voltage and the resistance are known within the circuit, then you can use the formula:

Current = Voltage / Resistance

If you know the amount of charge going past a certain location in a certain amount of time, then you can find the current using:

Current = charge / time

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Lora (of mass 47.4 kg) is an expert skier. She

Harrizon [31]

Answer:

Kinetic energy is 242.7 Joule

Explanation:

m = 47.4 kg

v = 3.2m/s²

Now,

K.E. = 1/2 × m × v²

or, K.E. = 1/2 × 47.4 × 3.2²

or, K.E. = 242.7 Joule

6 0

2 years ago

A 100 Ω resistor is connected in series with a 47 µF capacitor and a source whose maximum voltage is 5 V, operating at 100.0 Hz.

Pani-rosa [81]

Answer:

$X_c=-33.86275385\Omega$

$|Z|=105.5778675\Omega$

$I=0.04735841062A$

$\phi=20.78612878\°$

Explanation:

The electrical reactance is defined as:

$X_c=-\frac{1}{2\pi fC}$

Where:

$f=Frequency\\C=Capacitance$

So, replacing the data provided by the problem:

$X_c=\frac{1}{2\pi *100*(47*10^{-6} )} =-33.86275385\Omega$

Now, the impedance can be calculated as:

$Z=R+jX_c$

Where:

$R=Resistance\\X_c= Capacitive\hspace{3}reactance$

Replacing the data:

$Z=100-j33.86275385$

In order to find the magnitude of the impedance we can use the next equation:

$|Z|=\sqrt{(R^2)+(X_c^2)}=\sqrt{(100)^2+(-33.86275385)^2} =105.5778675\Omega$

We can use Ohm's law to find the current:

$V=I*Z\\I=\frac{V}{Z}$

Therefore the current is:

$I=\frac{5}{100-j33.86275385}=0.04485638113+0.01518960593j$

And its magnitude is:

$|I|=\sqrt{(0.04485638113)^2+(0.01518960593)^2} =0.04735841062\Omega$

Finally the phase angle of the current is given by:

$\phi=arctan(\frac{0.01518960593}{0.04485638113})=20.78612878\°$

5 0

2 years ago

What is the velocity of an object with a kinetic energy of 800 J and a mass of 12 kg?

Elis [28]

K.E = 1/2 mv²

800 = 1/2 ×12 ×v²

800 = 6 v²

800 / 6 = v²

= 133.4 =v²

√133.4 = √v²

11.5 = v²

I hope this answer is correct.

3 0

2 years ago

How does the quantum mechanical model of the atom describe electrons

Ulleksa [173]

The quantum mechanical model describes the allowed energies an electron can have. It also describes how likely it is to find the electrons in various locations around an atom's nucleus.

5 0

2 years ago

Match the term with the appropriate image

Tamiku [17]

First figure shows the object position

Second shows the image position

Third shows the focal length.

8 0

2 years ago