The maximum velocity in a banked road, ignoring friction, is given by;
v = Sqrt (Rg tan ∅), where R = Radius of the curved road = 2*1000/2 = 1000 m, g = gravitational acceleration = 9.81 m/s^2, ∅ = Angle of bank.
Substituting;
30 m/s = Sqrt (1000*9.81*tan∅)
30^2 = 1000*9.81*tan∅
tan ∅ = (30^2)/(1000*9.81) = 0.0917
∅ = tan^-1(0.0917) = 5.24°
Therefore, the road has been banked at 5.24°.
Answer:
780 m to travel north
Explanation:
6 m over = 750
53 degree so it will take about 2 min to reach the destination
106.68 centimetres are in 3.50 feet
Answer:
The answer is "".
Explanation:
Cavity and benzene should be extended in equal quantities.
Density = Mass divided by Volume