Is there anyone good at algebra 2 to solve this problem? I need help with part c.
1 answer:
Answer:
40 ft
Step-by-step explanation:
The maximum height of the ball is the y- coordinate of the vertex
Given a parabola in standard form then the x- coordinate of the vertex is
= -
h(t) = - 16t² + 48t + 4 ← is in standard form
with a = - 16, b = 48 , thus
= -
= 1.5
Substitute t = 1.5 into h(t) for max. height
h(1.5) = - 16(1.5)² + 48(1.5) + 4
= - 36 + 72 + 4
= 40
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Answer:
A
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (1, 1)
m = = - 2
note the line crosses the y- axis at (0, 3) ⇒ c = 3
y = - 2x + 3 → A