Answer:
A) 6
Explanation:
Complex III of the electron transport chain transfers four protons across the membrane during aerobic respiration, per pair of electrons. In the other hand, complex IV is responsible for transporting two protons (per pair of electrons) across the membrane.
If the given compound injects a pair of electron into complex III, four protons will accumulated due to complex III activity and then two more protons as these electrons move forward to complex IV. This means a total of 6 protons being transported to intermembrane space.
Genotype: 50% Aa and 50% aa
Phenotype: 50% Dimples and 50% no dimples
Explanation: Using a punnet square, we can figure out that the mother is recessive and the father is heterozygous. Putting the mother at the top of the square and the father on the side, you end up with the results above by crossing each square with the corresponding letters. It's okay if the letters end up backwards. Just be sure to face them the right direction, capitals being first once you finish.
Hope this helps!
In this case, it is given that the nucleus of the carrot cell is injected into the frog's egg lacking nucleus. In this case, the recipient egg (frog egg) would not be able to produce the carrot. Every species differ from from each other, sometimes, mating between closely related species can produce hybrid offspring, but frog and carrot cannot be combined at all in any aspect.
The carrot is a plant and the frog is an animal. All the physiological processes vary a lot in between plant and the animal. Hence, this growth would not be supported. So, it is impossible to generate a carrot by inserting it's nucleus in the frog's cell.
Answer:
water(H2O)
Explanation:
2C6H12O6-->C12H22O11+H2O
you can see that the difference between C12H24O12 and C12H22O11 is 2hydrogen atoms and an oxygen atom which are found in the water molecule also through hydrolysis you can bring that molecule of water back and restore two molecules of glucose
C12H22O11+H2O-->2C6H12O6
