Answer:
Explanation:
Given the simultaneous equation we are to find the values of x and y
3x-2y = 14 ..... ×1
5x-y = 32...... ×2
Using elimination method, the equation becomes
3x-2y = 14
10x-2y = 64
.subtract
3x-10x = 14-64
-7x = -50
x = -50/-7
x = 7 1/7
Substitute x = 50/7 into eqn 2
From 2;
5(50/7)-y = 32
250/7 - y = 32
y = 250/7-32
y = (250-224)/7
y = 26/7
Hence (x,y) = (50/7, 26/7)
I think is 1
hope it helpss!!!
1. compound
2. simple
3. compound-complex
4. fragment
5. compound
6. simple
7. complex
8. simple
9. compound-complex
10. fragment
