Please help me with this question step by step

two rectangular properties share a common side. Lot is 33 feet wide and 42 feet long. The combined area of the lots is 1,848 squ

klio [65]

First, find the area of lot A.

To find the area, multiply the length by the width.

33*42=1,386

Now, subtract the area of lot a from the total area. This will give us the area of lot b.

1,848-1,386=462

The area of lot b is 462 square feet.

Finally, divide the area of lot b (462) by its length to find the width. Since they both share a side, we know that it’s length is 42 feet.

462/42=11

Lot b is 11 feet wide.

Hope this helps!

4 0

2 years ago

App 19.study

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

2 years ago

nordsb [41]

Answer:

H0 : μ = 15

H1 : μ < 15

−6.170774

Step-by-step explanation:

Given :

n=115, barx =11.3, and s=6.43

H0 : μ = 15

H1 : μ < 15

−0.053658 ;

The test statistic :

(xbar - μ) ÷ s/sqrt(n)

(11.3 - 15) ÷ (6.43/sqrt(115))

Test statistic = −6.170774

Rejection region :

Reject Null ; if

Tstatistic < Zcritical

The P value is 0.00001 ; using the p value from Z calculator

Since,

P value < α

0.00001 < 0.05

Reject the null

6 0

2 years ago

Can you guys please help me with dis ill give you da crown da first one who answers

jeyben [28]

Hope u can see it : )

6 0

1 year ago

Read 2 more answers

how to find the area of each circle. use a calculator value of pi. round the answer to the nearest tenth

tankabanditka [31]

Answer:

A = 201.0 mi^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

We know that r = 8

A = (3.14) *8^2

A = 3.14 * 64

A = 200.96 mi ^2

Rounding to the nearest tenth

A = 201.0 mi^2

8 0

2 years ago

Read 2 more answers