<span>△ABC∼△DEF
</span>Height of <span>△ABC: h1=20 inches
</span>Height of △DEF: h2=24 inches
<span>Ratio of the area of △ABC to the area of △DEF: R=?
</span>
R=(h1/h2)^2
R=[ (20 inches) /(24 inches) ]^2
R=(5/6)^2
R=5^2/6^2
R=25/36
Answer: T<span>he ratio of the area of △ABC to the area of △DEF is 25/36</span>
Answer:
3844
Step-by-step explanation:
Answer:
i think ur answer is a im not 100 percent sure let me know if im wrong
Step-by-step explanation:
Answer:
5 m
Step-by-step explanation:
You know the area of a parallelogram is the product of its base length and height:
area = base × height
Fill in the given values, and solve for height:
60 m² = (12 m) × height
(60 m²)/(12 m) = height = (60/12) m
height = 5 m
The height is 5 meters.
It would be 6(4a2 - 3)
you would factor out just the 6 because the 18 doesn’t a a term with it like 34a2 does. then just divide normally to get ur answer 6(4a2 - 3)
