Can someone solve please , ill give Brainly to whoever is first.
1 answer:
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To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
[recall 
or 20(x+5) if you wish.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
Answer:
Step-by-step explanation:
Given
<em>See attachment</em>
Required
Determine the area of K
First, we need to calculate the length of the rectangle J
This gives:
Divide both sides by 22
So, the length of the rectangle J is 20.
Since both shapes are similar, then:
Substitute the known values:
Express as fraction:
Make Length, the subject of formula
The area of K is:
