In quadrant 2, x is negative which means x < 0. Also, in quadrant 2, y is positive so y > 0.
An example point that is located in quadrant 2 is the point (-5, 8). Note how the first coordinate is -5 so x = -5 which is negative. Furthermore, the second coordinate is 8 meaning that y = 8 which is positive.
Quadrant 2 is the quadrant on the upper left-hand side of the four quadrants on the xy coordinate system.
Answer:
x = 4
Step-by-step explanation:
ΔTRQ is an isosceles right triangle, so if we find the value of RT then the value of 'x' will be the same
We can find RT by creating a proportion based on the ratio of sides in a 30-60-90° triangle which, respectively, is 1 : : 2
2/RT = /2
cross-multiply:
· RT = 4
RT = 4
Therefore, x = 4
Step-by-step explanation:
I think the answer for the 3) is S=(a×ha)÷2= (7×4.2)÷2= 29,4 ÷2=14.7
And for the 5) one im really not sure.
Answer:
492,630
Logic is the only explanation I have for you...