What is the solution of the equation e^xe^2x = 4? Round your answer to the nearest hundredth.

1 answer:

8 0

The equation is:

[e^x] [e^(2x)] = 4

1) Applying property of multiplication of powers wiith same base =>

e ^ (x + 2x) = 4

=> e ^ (3x) = 4

2) Applying logarigth properties

3x = ln(4)

=> x = ln(4) / 3 ≈ 1.38629 / 3 ≈ 0.4621

Answer: x = ln(4) / 3 ≈ 0.4621

You might be interested in

Find a polar equation of the form r2=f(θ) for the curve represented by the cartesian equation x2−y2=1. (note the power of r in t

iragen [17]

The equations to transform from Cartesian to polar :
x = r cos θ , y = r sin θ
Or
x² = r² cos² θ , y² = r² sin² θ

To represent the Cartesian equation x²−y²=1
substitute with the values of x² and y²

∴ r² cos² θ - r² sin² θ = 1
 r² (cos² θ - sin² θ) = 1
but cos² θ - sin² θ = cos 2θ
∴ r² cos 2θ = 1
 r² = 1/cos 2θ

∴ r² = sec 2θ ⇒⇒⇒⇒ The required equation

4 0

2 years ago

Help with this :), please !

Assoli18 [71]

Answer:

make another one show the whole equation

8 0

2 years ago

What’s is x=5y for y

Margarita [4]

Answer:

$y=\frac{x}{5}$

Step-by-step explanation:

$\frac{x = 5y}{5}$

For the y to cancel out, you would have to divide y by 5. Whenever you do one thing to a side, you have to do the same on the other side. Once you do so, you'll get : $\frac{x}{5}$