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2 years ago

This diagram represents a function named h. Which of the choices also represents the function, h?

Mathematics

2 answers:

serg [7]2 years ago

6 0

Answer:

if this is on Imagine Math then its the first answer

Step-by-step explanation: got it right!

DerKrebs [107]2 years ago

3 0

Answer: x

Step-by-step explanation: because since you have h(x) from -2 then x4 is the same but your suppose to multiply the x4 with h so make it the same as -2 h(x)

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= Simplify the following algebraic expressions given below into their equivalent standard forms.

Dahasolnce [82]

Answer:

https://tex.z-dn.net/?f=(x%2B10)%5E%7B2%7D%20

Step-by-step explanation:

3 0

2 years ago

Cheryl is planning a garden that will be

GaryK [48]

Hello There!

Great Question!

To calculate the area of a rectangular prism, you would multiply the length, the width, and the depth. As we want to measure this in cubic feet, we should convert all of the measurements to feet to begin with.

How wide is the garden? (either 7 or 8 feet)

How long is the garden? (Whichever of 7 or 8 wasn’t used)

How deep is this garden? 6 inches.

Well, that’s not feet, right?

How many inches are in a foot? 12.

Divide 6 by 12, what is the answer? .5.

5 0

2 years ago

A room with a length of 270 cm and width 150 cm is to be covered with square tiles .What is the largest size of tiles to be used

Damm [24]

Find the greatest common factor of both numbers:

Factors for 150:

150: 1, 2, 5 , 6, 10, 15, 25, 30, 50, 75, 150

Factors for 270:

1, 2, 3, 5, 6 , 9, 10, 15, 18, 27, 30, 45, 54, 90, 135, 270

The largest number they both have in common is 30, so the largest tile could be 30 cm^2.

5 0

2 years ago

Write an algebraic expression for a C -5

Ivenika [448]

The answer is... Five less than C

4 0

2 years ago

1)cot a/2 -tan a/2 = 2 cot a<br>2) cot b/2 + tan b/2= 2 cosec b<br> prove

VladimirAG [237]

1)

LHS = cot(a/2) - tan(a/2)

= (1 - tan^2(a/2))/tan(a/2)

= (2-sec^2(a/2))/tan(a/2)

= 2cot(a/2) - cosec(a/2)sec(a/2)

= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))

= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)

= 2[(1+cos(a) -1)/sin(a)]

=2cot a

= RHS

2.

LHS = cot(b/2) + tan(b/2)

= [1 + tan^2(b/2)]/tan(b/2)

= sec^2(b/2)/tan(b/2)

= 1/sin(b/2)cos(b/2)

using product to sums

= 2/sin(b)

= 2cosec(b)

= RHS

8 0

2 years ago