Answer:
The probability that exactly 6 transactions will be made at an ATM in the next 20 minutes = 0.06306 = 0.0631 to 4d.p
Step-by-step explanation:
This is a Poisson distribution problem
The Poisson distribution formula is given as
P(X = x) = (e^-λ)(λˣ)/x!
where λ = mean = 10 transactions per 20 minutes
x = variable whose probability is required = 6 transactions in the next 20 minutes
P(X = 6) = (e⁻¹⁰)(10⁶)/6! = 0.06306
So, since the student makes $30 each week, we can disregard the number of hours.
So, we can model this situation by the following equation
9.5h+30
So, if he works 10.25 hrs (15 minutes = .25 of 1 hr) we just plug that number in
Since it's money we round to the nearest cent
So he will make $127.28 Next week
1/4 is the answer is is a lower fraction
0.45M+40
The M stands for the amount of minutes he went over.