Answer:
6/16 dogs will not be able to smell.
Explanation:
Genes A and B are considered for scent smell.
Individuals homozygous for either one or both of the nonfunctional recessive alleles are not able to smell.
The final cross would be AaBb x AaBb which has outcome of;
Individual with homozygous nonfunctional recessive alleles (bold ones):
- One nonfunctional recessive alleles: Aabb, aaBB, aaBb, Aabb, aaBb (5/16)
- Two nonfunctional recessive alleles: aabb (1/16)
- All nonfunctional recessive alleles: 6/16 dogs that could not smell scents
Answer:
e. PhoU keeps PhoR bound to the phosphate transporter protein Pst
Explanation:
PhoU is a membrane protein known to regulate the transport of phosphate (Pi) between cellular compartments. It has been discovered that mutations in this protein cause lethality because the cell becomes incapable of controlling the intracellular levels of Pi, this being toxic for the cell. PhoR is a histidine kinase/phosphatase. When the Pi level is considered to be a limiting factor, PhoR autophosphorylates at a histidine residue and then donates its phosphoryl group to PhoB. On the other hand, when the Pi level is high, this protein removes the phosphoryl group from phospho-PhoB. Finally, the Pst is a signal transduction protein that acts as a transporter capable of switching its conformation during the transport of PI.
Answer:
If both parents are heterozygous in a monohybrid cross, the offspring will have a phenotypic ratio of 3:1. If both are heterozygous for both traits in a dihybrid cross, the phenotypic ratio will be 9:3:3:1.
In biology, evolution is the change in the inherited traits of a population from generation to generation.
Common traits that have evolved in creatures are multicellular, heterotrophic, obtaining their energy by consuming energy-releasing food substances, reproduction and changes in cell structures.
My answer is an ostrich,a camel,and a fennec fox.
But the Fennec fox is the suitable answer...