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Answer:
The image of the point (1, -2) under a dilation of 3 is (3, -6).
Step-by-step explanation:
Correct statement is:
<em>What are the coordinates of the image of the point (1, -2) under a dilation of 3 with the origin.</em>
From Linear Algebra we get that dilation of a point with respect to another point is represented by:
(Eq. 1)
Where:
- Reference point with respect to origin, dimensionless.
- Original point with respect to origin, dimensionless.
- Dilation factor, dimensionless.
If we know that , and , then the coordinates of the image of the original point is:
The image of the point (1, -2) under a dilation of 3 is (3, -6).
The midpoint formula is ( x + x / 2, y + y / 2)
so....
6+ 2 = 8 / 2 = 4
4 + 8 = 12 / 2 = 6
the midpoint is (4, 6)
Step 2 is wrong and i don't know the other question