6 + 9x.....a common factor in both terms is 3
3(2 + 3x) <==
Answer:
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Step-by-step explanation:
Step-by-step explanation:
Answer:
0.049168726 light-years
Step-by-step explanation:
The apparent brightness of a star is
where
<em>L = luminosity of the star (related to the Sun)
</em>
<em>d = distance in ly (light-years)
</em>
The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.
Hence the apparent brightness of Alpha Centauri A is
According to the inverse square law for light intensity
where
light intensity at distance
light intensity at distance
Let be the distance we would have to place the 50-watt bulb, then replacing in the formula
Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.
Knowing the power rule:
dx*n*x^(n-1) all you'd need to do is bring the 7 down and multiply it by -3, then subtract 1 from 7. Because dx is 1 you don't need to worry about it (you'll use chain rule for that)
So your final answer should be dy/dx= -21x^6