For
y=a(x-h)^2+k
vertex is (h,k)
given
y=1(x-2)^2-5
the vertex is (2,-5)
tha'ts quadrant 4
andswer is 2nd one
(3.75, 5.5)
(Work is attached )
When using substitution , you substitute with a variable that is already by itself. In this case, the variable “y” is already by itself and equal to x+ 1.75 . you substitute that for the the y in the other equation and solve for the other variable which is “x”. After you solve for x , to find your y value, you have to substitute the x value in for either equation.
Answer:
Step-by-step explanation:
Srry
First, you need to set the equation equal to zero:
n^2 + 7n + 10 = 0
Now we factor. We need to find two numbers that add up to 7 and multiply to 10.
2 + 5 = 7
2 * 5 = 10
Now, we just need to write this as a polynomial:
(n + 2) (n + 5)
is our answer.
Hope this helps!