Answer:
0.000230144 N
Explanation:
n = Number of electrons = 
q = Charge of electron = 
k = Coulomb constant = 
r = Distance between obects = 1 m
The force would be
The force would be 0.000230144 N
Answer:
456.143684211 seconds
564.3 m
Explanation:
s = Distance
v = Velocity
Time is given by
Difference in time = 866.67-410.526315789 = 456.143684211 seconds
According to the question
The students would have to walk 564.3 m
Answer: cessation,cease,slowing momentum
Explanation:
Answer:
electric field E = (1 /3 e₀) ρ r
Explanation:
For the application of the law of Gauss we must build a surface with a simple symmetry, in this case we build a spherical surface within the charged sphere and analyze the amount of charge by this surface.
The charge within our surface is
ρ = Q / V
Q ’= ρ V
'
The volume of the sphere is V = 4/3 π r³
Q ’= ρ 4/3 π r³
The symmetry of the sphere gives us which field is perpendicular to the surface, so the integral is reduced to the value of the electric field by the area
I E da = Q ’/ ε₀
E A = E 4 πi r² = Q ’/ ε₀
E = (1/4 π ε₀) Q ’/ r²
Now you relate the fraction of load Q ’with the total load, for this we use that the density is constant
R = Q ’/ V’ = Q / V
How you want the solution depending on the density (ρ) and the inner radius (r)
Q ’= R V’
Q ’= ρ 4/3 π r³
E = (1 /4π ε₀) (1 /r²) ρ 4/3 π r³
E = (1 /3 e₀) ρ r
