The equation of the line is C. 1X/2 -2
How you figure this out is you first say when x is zero y is what?
y= 1/2 (0) - 2
You would then see that y=-2 (0,-2)
Plot that point
Next you need to find the slope of the line.
Remember slope is rise over run.
When you 'rise' up one (from -2) and 'run' 2
you are now at the point (2,-1) which is on the line.
You can continue doing rise/run along the line to check your answer.
I hope this makes sense! Let me know if you have any questions :)
Steps:
Use the divisor and find x :
x - 1 = 0 **add 1
x= 1
Now we will use the 1 in dividing:
take the coefficients from in front of all terms
** make sure you include 0's for x^2 and x since you have to have all terms
set it up with a 1 in a box:
1| 1 0 0 1 **bring the first number down
____________
1 **multiply the boxed number by the first number and add it to the second number
1| 1 0 0 1
____+1_____ **repeat with the rest of the terms
1 1
1| 1 0 0 1
___+1_+1_+1
1 1 1 2
**when you're done, use the new numbers to write an equation starting with a term with a degree one less than the previous equation.
**since there is a remainder, rewrite it divided by the original divisor
final answer:
x^2 + x + 1 + (2/ x -1)
Answer:
x = -3
Step-by-step explanation:
x is -3 in all values so we just write an equation.
4 is your answer have a nice day
Answer:
TQ = 10
Step-by-step explanation:
The diagonal divides the square into 2 right triangles with the diagonal being the hypotenuse.
Using Pythagoras' identity in triangle TPQ
TQ² = PQ² + PT²
TQ² = 10² + 10² = 100 + 100 = 200 ( take square root of both sides )
TQ = 
= 
= 
× = 10
