Answer:
547 m
Explanation:
From law of motion
s = ut + ½at²
Where "t" is Time taken to reach Earth
s= distance= 182 m
a= vertical acceleration = 5.82 m / s 2
U= initial velocity in vertical position = 0
182= ½ × 5.82t²
t²=( 2× 182)/ 5.82
= 364/5.82
= 62.54
t= √62.54
t= 7.908s
horizontal distance travelled = speed x time
Horizontal speed= 72.6 m / s
horizontal distance travelled =72.6× 7.908
= 547 m
Hence, the survivor will it hit the waves at 547 m away
Answer:
B
endothermic: heat taking in
exothermic: heat given out
Answer:
F = K Q1 Q2 / R^2 where K = 9 * 10E9 (1 / 4 pi ∈0)
F = 9.00E9 * (4.6E-16)^2 / .01 = 1.90E-19 N
Acceleration = (change in speed)/(time for the change)
Change in speed = (end speed) - (start speed)
Change in speed = (10 m/s) - (20 m/s) = -10 m/s
Time for the change = 5.00 seconds
Acceleration = (-10 m/s) / (5 sec)
<em>Acceleration = -2 m/s²</em>
That's choice-A .
Answer:
the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm
Explanation:
Given the data in the question;
wavelength of light; λ = 463 nm = 463 × 10⁻⁹ m
Index of refraction; n = 1.35
Now, the thinnest thickness of the soap film can be determined from the following expression;
= ( λ / 4n )
so we simply substitute in our given values;
= ( 463 × 10⁻⁹ m ) / 4(1.35)
= ( 463 × 10⁻⁹ m ) / 5.4
= ( 463 × 10⁻⁹ m ) / 4(1.35)
= 8.574 × 10⁻⁸ m
= 85.74 × 10⁻⁹ m
= 85.74 nm
Therefore, the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm