Shifting a graph up by c units involves adding c to the whole function
therefor
y=ax^2+c is c units higher than y=ax^2 (aka, it is shifted c units up)
This problem can be solved by manipulating the formula for power, which is: P = VI. Where:
P = Power in watts
V= Voltage in volts
I = Current in amperes
Since we are already given the power and voltage, simple substitution can be done.
P = VI
3.5 watts = 120 volts * I
I = 3.5 / 120
I = 0.0292 Amperes or 29.2 milliAmperes
Therefore, the current through the bulb is 29.2mA
Sub in the numbers
2(5)^2 - 4(5) + 5
=50 - 20 + 5
=30 + 5
=35
