Answer:
(7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance.
Step-by-step explanation:
We have a large sample size n = 56 research cotton samples. Besides, 
and 
. A 95% large-sample CI for the true average percentage elongation is given by 
, i.e., 
or equivalently (7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance because we have a large sample.
Answer:
Below.
Step-by-step explanation:
You can use any 4 x values, so we could have:
- 2 0 2 4
Now find the corresponding y values by substitution in the equation:
For x = -2, y = 1/2 *-2 + 2 = 1.
For x = 0, y = 1/2 * 0 + 2 = 2.
For x = 2 , y = 1/2* 2 + 2 = 3.
For x = 4 , y = 1/2 * 4 + 2 = 4.
So the table is:
-2 0 2 4
1 2 3 4
You then plot the points (-2, 1), (0, 2), (2, 3) AND (4, 4) on the grid and draw a line through them The graph will be a straight line.
Answer:
where is the question
Step-by-step explanation:
I don't see it.
The answer to your question is b. 2
Answer:
12x+24
Step-by-step explanation:
by multiplying the number 6 into the term inside of the bracket gives 12x + 24
