Nolan polled the 2 fastest swimmers on the swim team.

Pleaseee help help

Eddi Din [679]

The angle the golfer went off line from the tee when they drove the ball

is $\phi=28.2 \textdegree$ because the cosine rule has been applied to calculate the angle

From the question we are told that:

Distance of hole from tee $d_h=340yards$

Distance to the right $d_r=230yards$

Ball distance from hole $d_b=175 yard$

Given that the three points form a triangle x,y,z respectively

Where

$d_h=xz$

$d_r=xy$

$d_b=yz$

Using Cosine Rule

$yz^2=xy^2+xz^2-2(xy)(xz)cos\phi$

Therefore

$cos\phi=\frac{yz^2}{xy^2+xz^2-2(xy)(xz)}$

$cos\phi=\frac{(175)^2}{230^2+340^2-2(230)(340)}$

$cos\phi=0.88$

$\phi=28.2 \textdegree$

In conclusion the angle the golfer went off line from the tee when they

drove the ball is mathematically deducted and give as

$\phi=28.2 \textdegree$

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5 0

2 years ago

The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y.

Vaselesa [24]

<u>Answer:</u> The wavelength for X-rays with the given frequency is $1\times 10^{-10}m$

<u>Step-by-step explanation:</u>

To calculate the wavelength of light, we use the equation:

$\lambda=\frac{c}{\nu}$

where,

$\lambda$ = wavelength of the light

c = speed of light = $3\times 10^8m/s$

$\nu$ = frequency of light = $3\times 10^{18}s^{-1}$

Putting the values in above equation, we get:

$\lambda=\frac{3\times 10^8m/s}{3\times 10^{19}s^{-1}}=1\times 10^{-10}m$

Hence, the wavelength for X-rays with the given frequency is $1\times 10^{-10}m$

7 0

2 years ago

Read 2 more answers

A shirt originally cost $54.01, but it is on sale for $37.81. What is the percentage decrease of the price of the shirt? If nece

Marianna [84]

I think it's rounds at to 30

3 0

2 years ago

Jada bought 3 shirts that cost $19.99 each before discount. What was her total after the discount? The percentage discount at a

Alex777 [14]

Total after the discount would be $77.96

7 0

3 years ago

In a freshman class of 80 students,22 students take Consumer Education,20 students take French,and 4 students take both.Which eq

MAXImum [283]

<h3>Answer: Choice C</h3>

P = 11/40 + 1/4 - 1/20

=========================================================

Explanation:

The formula we use is

P(A or B) = P(A) + P(B) - P(A and B)

In this case,

P(A) = 22/80 = 11/40 = probability of picking someone from consumer education
P(B) = 20/80 = 1/4 = probability of picking someone taking French
P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes

So,

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 11/40 + 1/4 - 1/20

which is why choice C is the answer

----------------

Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.

6 0

2 years ago