Answer:
SSS
Step-by-step explanation:
bc all the sides are congruent.
I'm pretty sure the answer is the top right one because it looks really messed up. i mean, mi/hr*min doesn't equal mi, but im not too sure about the conversion part.
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when . So
Rouding up
We need a sample size of at least 719
-32^3/5
= (-2^5)^3/5
= -2^3
= -8
answer
-8
Answer:
The amount of oil was decreasing at 69300 barrels, yearly
Step-by-step explanation:
Given
Required
At what rate did oil decrease when 600000 barrels remain
To do this, we make use of the following notations
t = Time
A = Amount left in the well
So:
Where k represents the constant of proportionality
Multiply both sides by dt/A
Integrate both sides
Make A, the subject
i.e. At initial
So, we have:
Substitute in
To solve for k;
i.e.
So:
Divide both sides by 1000000
Take natural logarithm (ln) of both sides
Solve for k
Recall that:
Where
= Rate
So, when
The rate is:
<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>