Hey, i add an answer so you can give the other person brainlest :)
Aluminum has an atomic number of 13
with a mass number of 27
number of protons = mass number - atomic number = 27-13 = 14
Fe2O3 + 3CO --------> 2Fe + CO2
1 : 3 : 2 : 3
13.3 <--- 40 ------> 26.6 ---> 40 ( mol)
n = m/M
m CO2 = n.M = 13.3 . 40 = 532 ( g)
p/s : i hope that this will help ( cause i'm not really good at english :}}} )
Answer:
by watching and writing down the information that is provided
Explanation:
Answer:
stay the same.
Explanation: Period 3 consists of the full 1s, 2s, and 2p electron orbitals, plus the 3s and 3p valence orbitals, which are filled with a total of 8 more electrons as we move from left (Na) to the far right (Ar):
Na: 1s2 2s2 2p6 3s1
Ar: s2 2s2 2p6 3s2 3p6
As we move from left to right, and ignoring the already-filled 1s, 2s, and 2p orbitals, the period three starting and ending elements have the following:
Na: 3s1
Ar: 3s2, 3p6
All the new electrons electrons filled the third energy level (3s and 3p). So the energy level does not change, just the orbitals.
