Environmental costs of technological development include:
- depletion of non-renewable resources
- pollution of the atmosphere
- increased recycling of heavy metals
<h3>What are environmental costs of technological development?</h3>
The environmental costs of technological development refers to the effects on the environment of technological development.
These effects of technological development on the environment are usually negative and detrimental to the environment and the organisms found in the environment.
Some environmental costs of technological development include:
- depletion of non-renewable resources
- pollution of the atmosphere
- pollution of the land and water
- increased recycling of heavy metals
In conclusion, the negative environmental costs of technological development damage the environment.
Learn more about environmental costs of technology and development at: brainly.com/question/9839688
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Answer:
Momentum after = 2400 kgm/s
Explanation:
Momentum after = momentum before
Momentum after = m1v1 +m2v2
Momentum after = (600)(4) + (400)(0)
Momentum after = 2400 kgm/s
Answer:
88.89kg
Explanation:
The formula for mass is m=F/a. If we plug in the values, we get m=400N/4.5m/s^2. The mass is 88.89kg. We know that the unit is in kg because one newton (N) is 1kg*m/s^2. The m/s^2 is cancelled out by the acceleration, and we are left with kg.
Answer:
lowest frequency = 535.93 Hz
distance between adjacent anti nodes is 4.25 cm
Explanation:
given data
length L = 32 cm = 0.32 m
to find out
frequency and distance between adjacent anti nodes
solution
we consider here speed of sound through air at room temperature 20 degree is approximately v = 343 m/s
so
lowest frequency will be = ..............1
put here value in equation 1
lowest frequency will be =
lowest frequency = 535.93 Hz
and
we have given highest frequency f = 4000Hz
so
wavelength = ..............2
put here value
wavelength =
wavelength = 0.08575 m
so distance = ..............3
distance =
distance = 0.0425 m
so distance between adjacent anti nodes is 4.25 cm
Answer:
#_photons = 30 photons / s
Explanation:
Let's start by finding the energy of a photon of light, let's use the Planck relation
E = h f
the speed of light is related to wavelength and frequency
c = λ f
we substitute
E = h c /λ
E₀ = 6.63 10⁻³⁴ 3 10⁸/500 10⁻⁹
E₀ = 3.978 10⁻¹⁹ J
now let's use a direct proportion rule. If the energy of a photon is Eo, how many fornes has an energy E = 1.2 10⁻¹⁷ J in a second
#_photons = 1 photon (E / Eo)
#_photons = 1 1.2 10⁻¹⁷ /3.978 10⁻¹⁹
#_photons = 3.0 10¹
#_photons = 30 photons / s