Answer:
- <em>The molar mass of an element is the mass of </em><u>one mole of atoms of the element.</u>
Explanation:
<em>The molar mass of an element </em>is its atomic mass, i.e. the mass in grams of one mole of atoms of the element.
Remember 1 mol is approximately 6.022 × 10²³.
So, 1 mol of atoms is 6.022 × 10²³ atoms.
The molar mass is an average: it is the weighted average mass of the natural isotopes of the element, taking into account their relative abundance.
For example, the molar mass or atomic mass of carbon is 12,0107 g/mol, instead of 12.0000, becasue carbon exists in several forms (isotopes), and so the weighted average is not a whole number.
Answer:
7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.
Explanation:
First of all the molecular weight of Na2SO4 is 142.08 gram.Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.
According to the given question we have to prepare 0.100 M solution
1000 ml of solution contain 142.08×0.1= 14.208 gram Na2SO4
1 ml of solution contain 14.208÷1000= 0.014 gram
0.5L or 500ml of solution contain 0.014×500= 7gram Na2SO4.
So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.
Carbohydrates,Lipids,Proteins,Nucleic acids,<span>Organic Compounds</span>
= 9.1 × 10^6
(scientific notation)
= 9.1e6
(scientific e notation)
= 9.1 × 10^6
(engineering notation)
(million; prefix mega- (M))
= 9100000
<span>(real number)</span>