From the 3 options listed, both
in and
in could be measures found using a ruler with eighth inches marked, because those decimals can be written in terms of eighth fractions.
The other option,
in, is not a possibility because 0.1 cannot be written as a fraction of 8 that is marked on the ruler.
Answer:
If you comment fractions I will do them!
Step-by-step explanation:
Across:
A = 46
E = can't see the fraction
H = 2111
I = 64
J = 29
L = can't see the fraction
P = 55005
R = can't see the fraction
S = 21
T = 49
U = 308
V =129
X = can't see the fraction
Y = 4008
Z = 15
BB = 375
EE = 65
FF = 16
GG = 64
Down:
B = 600
C = can't see the fraction
D = 316
G = can't see the fraction
H = can't see the fraction
K = 9520
L = 15010
N = 299
O = 59
Q = 518
T = 4116
U = 333
V = 1006
W = 189
AA = 55
CC = 71
DD = 56
Answer:
14 elliptical machines
Step-by-step explanation:
t = # of treadmills
e = # of elliptical machines
t + e = 38
t = e + 10
Substitute:
e + 10 + e = 38
2e = 28
e = 14
Answer:
2.5 + 3<em>h</em> = 13
Step-by-step explanation:
2.5 for the hotdog.
3 for each hamburger
3.5$ for each hamburger as h
Hope this Helps!
<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given = 
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>
Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases
Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0
and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>
which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write
where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0 and g2 = 9.8
We get h1 = 3.67m which is the required height
