<h3><u>Solution: </u></h3>
Radius of Cylindrical Pillar , r = 28 Cm = 0.28 m.
Curved surface area of a Cylindrical = 2πrh.
Curved surface area of a pillar -
Curved surface area of 24 such Pillar :-
(7.04 x 24 = 168.96m²)..
- Cost of painting an area of 1 m² = Rs8...
• Therefore , cost of painting 1689.6m² :-
( 168.96 x 8 = Rs 1351.68)...
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Answer:
36
Step-by-step explanation:
Objective: Find missing dimensions of the right triangle using the then subtract that area of the triangle from the rectangle's area.
Using the definition of a rectangle, the left vertical side measure is 7 and right vertical side is 6. So the missing legs of the triangle is 4 and 3.
Apply triangle formula, base x height divided by 2.
Area of rectangle is length x width so the area is
Subtract 6 from 42.
I think the answer to this is .6 or 1.7
The general equation for a circle,
, falls out of the Pythagorean Theorem, which states that the square of the hypotenuse of a right triangle is always equal to the sum of the squares of its legs (you might have seen this fact written like
, where <em>a </em>and <em>b</em> are the legs of a right triangle and <em>c </em>is its hypotenuse. When we fix <em /><em>c</em> in place and let <em>a </em>and <em>b </em>vary (in a sense, at least; their values are still dependent on <em>c</em>), the shape swept out by all of those possible triangles is a circle - a shape defined by having all of its points equidistant from some center.
How do we modify this equation to shift the circle and change its radius, then? Well, if we want to change the radius, we simply have to change the hypotenuse of the triangle that's sweeping out the circle in the first place. The default for a circle is 1, but we're looking for a radius of 6, so our equation, in line with Pythagorus's, would look like
, or
.
Shifting the center of the circle is a bit of a longer story, but - at first counterintuitively - you can move a circle's center to the point (a,b) by altering the x and y portions of the equation to read: