Answer:
c
Step-by-step explanation:
Answer:
a) ∫_{-6}^{6} ∫_{0}^{36} ∫_{x²}^{36} (-y) dy dz dx
b) ∫_{0}^{36} ∫_{-6}^{6} ∫_{x²}^{36} (-y) dy dx dz
c) ∫_{0}^{36} ∫_{x²}^{36} ∫_{-6}^{6} (-y) dx dy dz
e) ∫_{x²}^{36} ∫_{-6}^{6} ∫_{0}^{36} (-y) dz dx dy
Step-by-step explanation:
We write the equivalent integrals for given integral,
we get:
a) ∫_{-6}^{6} ∫_{0}^{36} ∫_{x²}^{36} (-y) dy dz dx
b) ∫_{0}^{36} ∫_{-6}^{6} ∫_{x²}^{36} (-y) dy dx dz
c) ∫_{0}^{36} ∫_{x²}^{36} ∫_{-6}^{6} (-y) dx dy dz
e) ∫_{x²}^{36} ∫_{-6}^{6} ∫_{0}^{36} (-y) dz dx dy
We changed places of integration, and changed boundaries for certain integrals.
1 clipe..............7/8
x.......................56
7x/8 = 56
7x = 56*8
x = 56*8/7
x = 8*8
x = 64 clipes
1 clipe = 0,03
64 clipes = 0,03*64
64 clipes = 1,92
The top graph is correct because an x=# will create a vertical line at that #
Answer:
sin(B) = 4/5
cos(B) = 3/5
tan (B) = 4/3
Step-by-step explanation:
soh cah toa