If Damon goes from his office on the 10th floor to a meeting

Please help with this math problem! The intersection of GK and HL is point P. Which triangle must be an isosceles triangle? *loo

Whitepunk [10]

None of the triangles listed has two equal base angles or two equal side lengths, therefore: D. No triangle is isosceles.

<h3>Properties of an Isosceles Triangle</h3>

An isosceles triangle has two base angles having equal angle measure.
The side lengths that are opposite each of the equal base angles are also congruent to each other.

Thus, none of the triangles listed has two equal base angles or two equal side lengths, therefore: D. No triangle is isosceles.

Learn more about isosceles triangle on:

brainly.com/question/11884412

5 0

2 years ago

Helpppppp plsssssssss

bekas [8.4K]

Answer:

C

Step-by-step explanation:

The right triangle on the right side of the figure has a height of 6 (two same sides lengths) and a base of 3.

x is the hypotenuse (side opposite of 90 degree angle).

We can use the pythagorean theorem to find x. The pythagorean theorem tells us to square each leg (height and base) of the triangle and add it. It should be equal to the hypotenuse square.

For this triangle it means, we square 6 and 3 and add it. It should be equal to x squared. Then we can solve. Shown below:

$6^2 + 3^2 = x^2\\36 + 9 = x^2\\45 = x^2\\x=\sqrt{45}$

<em>Now we can use property of radical $\sqrt{x}\sqrt{y} =\sqrt{x*y}$ to simplify:</em>

$x=\sqrt{45} \\x=\sqrt{5*9} \\x=\sqrt{5} \sqrt{9} \\x=3\sqrt{5}$

Correct answer is C

6 0

2 years ago

Read 2 more answers

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$