Which system of equations has infinitely many solutions?
1 answer:
Answer: B.
Step-by-step explanation:
Let's solve your system by elimination.
4x−2y=8;−2x+2y=6
Add these equations to eliminate y:
4x-2y=8
-2x+2y=6
2x=14
Substitute 7 for x in 4x−2y=8:
(4)(7)−2y=8
−2y+28=8 (Simplify both sides of the equation)
−2y+28+−28=8+−28 (Add -28 to both sides)
−2y=−20
−2y/−2=−20/−2 (Divide both sides by -2)
y=10
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Answer:
Step-by-step explanation:
Factorise the numerator and denominator
8a² - 2 ← factor out 2 from each term
= 2(4a² - 1) ← 4a² - 1 is a difference of squares
= 2(2a - 1)(2a + 1)
4a² + 4a + 1 ← is a perfect square
= (2a + 1)²
Thus
= ← cancel (2a + 1) on numerator/ denominator
=
=