Lime m is neither because it does not have the opposite reciprocal nor same slope.
Line n is perpendicular because it has the opposite reciprocal.
Line p is neither because it does not have the opposite reciprocal nor same slope.
Line q is parallel because it has the same slope.

7 0

2 years ago

M angle 3= 31°. Find m angle 4 (complementary angle)

solniwko [45]

Hi, there.

________

$\boxed{\begin{minipage}{8cm} Complementary angles \\ Complementary angles are angles whose sum \\ is 90^\circ. \text{Using this info, let's consider this:} \\ \text{If an angle's measure is 31 degrees, what's} \\ \text{its \ complement?}\end{minipage}}$

$\text{Set up an equation, letting a be the unknown angle}$

$\bold{a+31=90}\\\text{Subtract 31 from both sides}\\\bold{a=59}$

Hope the answer - and explanation - made sense,

happy studying!!

6 0

1 year ago

Vector u has its initial point at (-7, 2) and its terminal point at (11, -5). Vector v has a direction opposite that of vector u

salantis [7]

$\bf u\implies 
\begin{cases}
(-7,2)\\
(11,5)
\end{cases}\implies [11-(-7)]~,~[5-2]\implies (11+7)~,~(5-2)
\\\\\\
\stackrel{\textit{component form}}{\ \textless \ 18~,~3\ \textgreater \ }\\\\
-------------------------------\\\\
||u||=\sqrt{18^2+3^2}\implies ||u||=\sqrt{333}\implies ||u||=\sqrt{9\cdot 37}
\\\\\\
||u||=\sqrt{3^2\cdot 37}\implies ||u||=3\sqrt{37}\\\\
-------------------------------$

$\bf \ \textless \ -18~,~-3\ \textgreater \ \impliedby \textit{opposite vector to \underline{u}}
\\\\\\
3\cdot 3\sqrt{37}\implies 9\sqrt{37}\impliedby \textit{3 times the magnitude of \underline{u}}
\\\\\\
3\ \textless \ -18,-3\ \textgreater \ \implies \stackrel{\textit{component form of "v"}}{\ \textless \ -54~,~-9\ \textgreater \ }\impliedby \textit{3 times as long as \underline{u}}$

7 0

2 years ago

Read 2 more answers

Graph the line y=-2x-3

Elina [12.6K]

Answer:

See attached picture.

Step-by-step explanation:

To graph the line, start at (0,-3) since b = -3 in the equation. This is the y-intercept. Mark this point. From this point, move down 2 units and to the right 1 unit. Mark this new point at (1,-1). Connect the points with a line. See attached picture.

7 0

2 years ago