Answer:
The forklift truck can raise maximum of 43 boxes.
Step-by-step explanation:
We are given the following in the question:
Maximum limit of forklift truck =
1750 kilograms
Let x be the number of 40 kilogram boxes that this forklift truck can raise.
Thus, we can write the following inequality that describes the maximum number of boxes raised.
Thus, the forklift truck can raise maximum of 43 boxes.
Answer:
Step-by-step explanation:
The balance (b) in Sam's account will be the initial balance less 20 times the number of weeks (w) that he withdraws gas money.
b = 2450 -20w
We want the inequality to express the condition that this balance is below 1000:
b < 1000
2450 -20w < 1000 . . . . . substitute for b
__
The solution to this can be found by subtracting 2450, then dividing by -20.
-20w < -1450
w > 72.5
If weeks are counted in whole numbers, Sam's balance will be below $1000 after 73 weeks.
Factors are what is being multiplied or divided. In this problem, you have 6 times X times Y. So, you have 3 factors.
Answer:
95%if i aint tripping of da gas
Step-by-step explanation:
