If f(x)=2x+5 and g(x)=x²+5, evaluate the functions:

Mathematics

2 answers:

Allushta [10]2 years ago

4 0

Answer:

f(-3) = -1

g(-3) = 14

Step-by-step explanation:

f(x) = 2x+5

f(-3) = 2(-3) + 5

f(-3) = -6 + 5

f(-3) = -1

g(-3) = -3^2 + 5

g(-3) = 9 + 5

g(-3) = 14

Ostrovityanka [42]2 years ago

3 0

Answer:

f(-3) = -1

g(-3) = 14

Step-by-step explanation:

plug -3 for x to get the answer

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If sin theta= - 5/7, which of the following are possible?

Sphinxa [80]

Answer:

$\large\boxed{\sec\theta=\dfrac{7}{\sqrt{24}},\ and\ \tan\theta=-\dfrac{5}{\sqrt{24}}}\\\boxed{\cos\theta=\dfrac{\sqrt{24}}{7},\ and\ \tan\theta=\dfrac{5}{\sqrt{24}}}$

Step-by-step explanation:

$\text{Use:}\\\\\sin^2\theta+\cos^2\theta=1\to\cos\theta=\pm\sqrt{1-\sin^2\theta}\\\\\tan\theta=\dfrac{\sin\theta}{\cos\theta}\\\\\sec\theta=\dfrac{1}{\cos\theta}\\\\==========================\\\\\sin\theta=-\dfrac{5}{7}\\\\\cos\theta=\pm\sqrt{1-\left(-\frac{5}{7}\right)^2}=\pm\sqrt{1-\frac{25}{49}}=\pm\sqrt{\frac{24}{49}}=\pm\dfrac{\sqrt{24}}{\sqrt{49}}=\pm\dfrac{\sqrt{24}}{7}\\\\\sec\theta=\pm\dfrac{1}{\frac{\sqrt{24}}{7}}=\pm\dfrac{7}{\sqrt{24}}$

$\tan\theta=\pm\dfrac{-\frac{5}{7}}{\frac{\sqrt{24}}{7}}=\mp\dfrac{5}{7\!\!\!\!\diagup_1}\cdot\dfrac{7\!\!\!\!\diagup^1}{\sqrt{24}}=\mp\dfrac{5}{\sqrt{24}}$