<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
14 of the machine that cost $150 was sold and 8 of the machine that cost $225 was sold.
To solve this problem, we would write a system of linear equations.
- Let x represent the machine that cost $150
- Let y represent the machine that cost $225
We can proceed to write our equations now.
From equation 1
<h3>The Value of Y</h3>
put equation (iii) into (ii)
<h3>The Value of X</h3>
Since we know the number of y, we can simply substitute it into equation (i) and solve.
From the calculations above, 14 of the machine that cost $150 was sold and 8 of the machine that cost $255 was sold.
Learn more about system of equations here;
brainly.com/question/13729904
Answer:(x+3)(3x+4)
Step-by-step explanation:
Answer:
0.8104
Step-by-step explanation:
Answer:
a. 5
Step-by-step explanation:
arrange
1 2 3 5 5 6 6 6 8 9 9 10 10 11 12 13
median=6+8/2=7
range=13-1=12
difference=12-7=5
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